Sunday, December 15, 2019
Maths Coursework- Matrix Investigation Free Essays
Maths SL Matrix Investigation I will try to investigate in powers of matrices (2Ãâ"2). Also, try to find a pattern, if there is one. A=[pic] Using my GCD calculator to raise matrix A to different powers [pic]= [pic] [pic]= [pic] [pic]=[pic] [pic]= [pic] [pic]= [pic] [pic]= [pic] [pic]=[pic] The pattern that I can see is that when the power of matrix A is an even number e. We will write a custom essay sample on Maths Coursework- Matrix Investigation or any similar topic only for you Order Now g. 2,4,6,8 then the result is [pic] the identity matrix. However, when the power is an odd number the matrix stays the same so [pic] My prediction for [pic] matrix is: [pic] Using the GCD calculator I checked my answer and it is correct. The determinant for this matrix A is -1 because (1x(-1)-0x3), that means that if we multiply A with the inverse of A so [pic] the result would be [pic] identity matrix. [pic]= [pic] [pic] [pic] which basically shows us that the inverse of this matrix is the same as the original one. A general rule for [pic](using algebra) When the ââ¬Ënââ¬â¢ is an even number [pic]= A[pic] when the ââ¬Ënââ¬â¢ is an odd number [pic]= A(A[pic] Itââ¬â¢s basically really simple one because of the determinant, which was -1, so when we make it as a fraction [pic] the result is still the same. Now, I am considering the matrix B= [pic] Using my GCD calculator I am calculating B raised to different powers. [pic]= [pic] [pic]= [pic] [pic]= [pic] [pic]= [pic] [pic]= [pic] The determinant of this matrix is -4 so probably the formula from before would not work because itââ¬â¢s not an identity matrix. But what we can see it is somehow related to the identity matrix. Because of the first result, which is just squaring, is 4x[pic] From these calculations I can see that the formula for an even powers would be: [pic]= [pic] so [pic]= [pic] = [pic] [pic]= [pic] = [pic] And when the power is an odd number det= -4 [pic]= [pic][pic] [pic] so [pic]= [pic] = [pic]=[pic] [pic]= [pic] = [pic]=[pic] My prediction for [pic] would be [pic]= [pic] = [pic]=[pic]= [pic] =[pic] As I checked it using my GCD calculator and it is right we can consider that the formula is working for matrix B, which has a determinant equal to -4 Now I am trying to generalized this rule and try different values for a, b and n. pic] Using the GCD [pic]= [pic] [pic]= [pic] Checking with the formula (the determinant is equal to -16) [pic] So [pic] [pic]= [pic] = [pic]= [pic] Using the GCD and formula to see if the pattern is working: [pic]=[pic] [pic] So [pic] (the determinant is equal to -9) [pic]=[pic] [pic]=[pic]=[pic] [pic]=[pic] [pic]= [pic] The formula works so far, however now I am going to try raise matrix to a negative power and see, if the formula is working: [pic] I canââ¬â¢t put it into the calculator. But we know that when we raise something to the negative power is the same as: e. g. [pic] = [pic] [pic]=[pic] [pic] [pic]=[pic] [pic]= [pic] The rule for negative powers make sense, we would always end up with 1 over matrix. So simply saying when the n was a positive odd number the matrix was [pic] and when n was the same but negative the result was [pic] so almost the same but every element in the matrix was 1 over the result from the positive. Now I am going to try a different value for b: [pic] = [pic] [pic]= [pic] pic] = [pic] [pic]=[pic] We could also consider the power n= [pic] [pic] Which we can rearrange as [pic] We canââ¬â¢t really use the pattern here because we cannot square root the matrices The results hold true in general because the third element(c) was always 0. Which made the determinant always a negative number and multiplication of two the same numbers e. g. (2x-2) (3x-3) It is important because of the rule, so when we use odd numbers as a power a formula is th at n-1 which makes it an even number, which then is divided by two. Now, I will consider powers of the form [pic] Using the GCD: [pic]= [pic] the determinant is equal to(-4-4)=-8 [pic]=[pic] [pic]= [pic] so [pic] = [pic] [pic]= [pic] so [pic] [pic]= 64[pic]=[pic] [pic] determinant = -19 [pic]= [pic] =[pic] [pic]= [pic] =[pic] it doesnââ¬â¢t work [pic]= [pic] =[pic]= [pic] [pic]= [pic] =[pic]= [pic] when I do [pic]= [pic] the formula doesnââ¬â¢t work anymore so Iââ¬â¢ll try this one [pic]= [pic] [pic] = [pic] which is the same as in the calculator etââ¬â¢s see with the other matrix [pic] the determinant= -19 [pic]= [pic] = [pic] [pic]= [pic] =[pic]= [pic] [pic]= [pic] [pic] = [pic] As we can see the generalized rule is: For even powers: [pic]= [pic] Now I need to find out the formula for odd powers [pic]= [pic] so [pic] [pic]= 64[pic]=[pic] [pic] [pic] the determinant =-19 [pic]=[pic] [pic]= 19 [pic]= [pic] [pic]=[pic] [pic]=[pic] Using my GCD I checked the answer and itââ¬â¢s the same. The general rule for odd powers: [pic]= [pic] How to cite Maths Coursework- Matrix Investigation, Papers
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment
Note: Only a member of this blog may post a comment.